## Question

300 g of water at 25^{o}C is added to 100 g of ice at 0^{o}C. The final temperature of the mixture is

### Solution

0^{o}C

Let the temperature of the mixture be *t*^{o}C. Heat lost by water in calories

Heat in calories required to melt 100 g of ice

Now Heat lost = Heat gained

Or 7500 – 300*t* = 8000

Or ^{o}C

Since *t* is negative, the water at 25^{o}C cools to 0^{o}C and melts a part of ice at 0^{o}C.

.

Hence only a part of the ice melts and resulting temperature is **0 ^{o}C**.

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